Hi Sheyda,Thanks for the question :)So you would expand brackets, same way as you might if you had for example2(x + y)In this case, you would multiply each term in the bracket by _/3.So it becomes:(_/3 x 2) + (_/3 x _/3)For (_/3 x 2), we just say it becomes 2_/3 as we cannot simplify this any further. I can explain that in more detail if you need.For (_/3 x _/3), we use the rule that multiplying surds is the same as multiplying the numbers in each original surd together in one surd - this is notated as_/y x _/z = _/(yz)So here we have _/(3 x 3), which is _/9, which is obviously just 3.Therefore, your final answer becomes the sum of the two brackets, which is 2_/3 + 3. As this can’t be further simplified, this is how you would give your answer.
You would have to multiply square root 3 by 2 and square root 3 and then add them. So square root 3 multiplied by 2 is 2 square root 3 and square root 3 multiplied by square root 3 is 3. Therefore your answer is 2 square root 3 plus 3
Hi Sheyda, Thanks for the question :) So you would expand brackets, same way as you might if you had for example 2(x + y) In this case, you would multiply each term in the bracket by _/3. So it becomes: (_/3 x 2) + (_/3 x _/3) For (_/3 x 2), we just say it becomes 2_/3 as we cannot simplify this any further. I can explain that in more detail if you need. For (_/3 x _/3), we use the rule that multiplying surds is the same as multiplying the numbers in each original surd together in one surd - this is notated as _/y x _/z = _/(yz) So here we have _/(3 x 3), which is _/9, which is obviously just 3. Therefore, your final answer becomes the sum of the two brackets, which is 2_/3 + 3. As this can’t be further simplified, this is how you would give your answer.
You would have to multiply square root 3 by 2 and square root 3 and then add them. So square root 3 multiplied by 2 is 2 square root 3 and square root 3 multiplied by square root 3 is 3. Therefore your answer is 2 square root 3 plus 3